(x^2+2x)^(1/5)=-1

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Solution for (x^2+2x)^(1/5)=-1 equation: 



(x^2+2x)^(1/5)=-1

We move all terms to the left:

(x^2+2x)^(1/5)-(-1)=0

We add all the numbers together, and all the variables

(x^2+2x)^(+1/5)-(-1)=0

We add all the numbers together, and all the variables

(x^2+2x)^(+1/5)+1=0

We multiply all the terms by the denominator


(x^2+2x)^(+1+1*5)=0

We add all the numbers together, and all the variables

(x^2+2x)^6=0

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